In article <38764dcf@news.povray.org>, "omniVERSE" <inv### [at] aolcom> 
wrote:

> Whoa, did I not catch on to this reasoning at all!
> If x=3 it will be x=3 when 2*x??
> Okay, I'm lost.  Unless it's a average of the noise function....

No, if the function returns a certain value at 6 units along the x 
axis(x=6), than if it is given 2*x instead of x, it will think x=6 when 
it is really x=3. So the value that showed up at 6 units now shows up at 
3 units.

N=What the function "sees"
V=The real value

With N=V:

  0   1   2   3   4   5   6
N |   |   |   |   |   |   |

  0   1   2   3   4   5   6
V |   |   |   |   |   |   |


With N=2*V

  0 1 2 3 4 5 6
N | | | | | | |

  0   1   2   3   4   5   6
V |   |   |   |   |   |   |

See what I mean now? If the function returned A at x=6 when given x, it 
will give A at x=3 when given 2*x.

Sorry, I am not good at explaining this kind of thing.

-- 
Chris Huff
e-mail: chr### [at] yahoocom
Web page: http://chrishuff.dhs.org/

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